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=21Y^2-46Y+24
We move all terms to the left:
-(21Y^2-46Y+24)=0
We get rid of parentheses
-21Y^2+46Y-24=0
a = -21; b = 46; c = -24;
Δ = b2-4ac
Δ = 462-4·(-21)·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-10}{2*-21}=\frac{-56}{-42} =1+1/3 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+10}{2*-21}=\frac{-36}{-42} =6/7 $
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